Subtract 40/42 from 16/9, Solve 1 7/9

Subtract 40/42 from 16/9

1^st number: 1 7/9, 2^nd number: 40/42

16/9 - 40/42 is 52/63.

Find the least common denominator or LCM of the two denominators:
LCM of 9 and 42 is 126

Next, find the equivalent fraction of both fractional numbers with denominator 126
For the 1st fraction, since 9 × 14 = 126,
16/9 = 16 × 14/9 × 14 = 224/126
Likewise, for the 2nd fraction, since 42 × 3 = 126,
40/42 = 40 × 3/42 × 3 = 120/126
Subtract the two like fractions:
224/126 - 120/126 = 224 - 120/126 = 104/126
After reducing the fraction, the answer is 52/63

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