Subtract 6/12 from 40/2, Solve 20 0/2

Subtract 6/12 from 40/2

1^st number: 20 0/2, 2^nd number: 6/12

40/2 - 6/12 is 39/2.

Find the least common denominator or LCM of the two denominators:
LCM of 2 and 12 is 12

Next, find the equivalent fraction of both fractional numbers with denominator 12
For the 1st fraction, since 2 × 6 = 12,
40/2 = 40 × 6/2 × 6 = 240/12
Likewise, for the 2nd fraction, since 12 × 1 = 12,
6/12 = 6 × 1/12 × 1 = 6/12
Subtract the two like fractions:
240/12 - 6/12 = 240 - 6/12 = 234/12
After reducing the fraction, the answer is 39/2
In mixed form: 191/2

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