Answers

Subtract 90/6 from 42/32

1^st number: 1 10/32, 2^nd number: 15 0/6

42/32 - 90/6 is -219/16.

Steps for subtracting fractions

1. Find the least common denominator or LCM of the two denominators:
   LCM of 32 and 6 is 96
   
   Next, find the equivalent fraction of both fractional numbers with denominator 96
2. For the 1st fraction, since 32 × 3 = 96,
   42/32 = 42 × 3/32 × 3 = 126/96
3. Likewise, for the 2nd fraction, since 6 × 16 = 96,
   90/6 = 90 × 16/6 × 16 = 1440/96
4. Subtract the two like fractions:
   126/96 - 1440/96 = 126 - 1440/96 = -1314/96
5. After reducing the fraction, the answer is -219/16

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