Subtract 7/12 from 56/40, Solve 1 16/40

Subtract 7/12 from 56/40

1^st number: 1 16/40, 2^nd number: 7/12

56/40 - 7/12 is 49/60.

Find the least common denominator or LCM of the two denominators:
LCM of 40 and 12 is 120

Next, find the equivalent fraction of both fractional numbers with denominator 120
For the 1st fraction, since 40 × 3 = 120,
56/40 = 56 × 3/40 × 3 = 168/120
Likewise, for the 2nd fraction, since 12 × 10 = 120,
7/12 = 7 × 10/12 × 10 = 70/120
Subtract the two like fractions:
168/120 - 70/120 = 168 - 70/120 = 98/120
After reducing the fraction, the answer is 49/60

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